NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2, are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2.

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2

Question 1.

Find the area of the following parallelograms :





Solution:

Question 2.

Find the area of each of the following triangles :





Solution:

Question 3.

Find the missing values :



Solution:

Question 4.

Find the missing values :



Solution:

Question 5.

PQRS is a parallelogram (in Figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM =7.6 cm. Find :

(a) the area of the parallelogram PQRS

(b) QN, if PS = 8 cm.



Solution:

(a) Area of the parallelogram PQRS = base × height = SR × QM = 12 × 7.6 cm² = 91.2 cm²

(b) Area of the parallelogram PQRS = base × height = PS × QN

⇒ 91.2 = 8 × QN

⇒ QN =  cm

⇒ QN = 11.4 cm.

Question 6.

DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (in Figure). If the area of parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL.



Solution:

Question 7.

∆ ABC is right-angled at A (in Figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ ABC. Also find the length of AD.



Solution:

Question 8.

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?



Solution:

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