RS Aggarwal Solutions Class 10 Chapter 11 Arithmetic Progressions MCQS

RS Aggarwal Solutions Class 11 Chapter 11 Arithmetic Progressions MCQS

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 11 Arithmetic Progressions

Choose the correct answer in each of the following questions.

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

Question 6.

Solution:

Question 7.

Solution:

Question 8.

Solution:

Question 9.

Solution:

Question 10.

Solution:

Question 11.

Solution:

Question 12.

Solution:

Question 13.

Solution:

Question 14.

Solution:

Sum of first n odd natural numbers = (n)²

Sum of first 20 odd natural numbers = (20)² = 400 (c)

Question 15.

Solution:

First 40 positive integers divisible by 6 are 6, 12, 18, 24, … to 40 terms

Here, a = 6, d = 6, n = 40

Question 16.

Solution:

Question 17.

Solution:

Question 18.

Solution:

In an AP,

a₁₈ – a₁₄ = 32

Let a be the first term and d be the common difference, then

Question 19.

Solution:

Question 20.

Solution:

Question 21.

Solution:

Question 22.

Solution:

Question 23.

Solution:

Question 24.

Solution:

Question 25.

Solution:

Sum of first 16 terms of AP 10, 6, 2, …

Here, a = 10, d = 6 – 10 = -4, n = 16

Question 26.

Solution:

Question 27.

Solution:

Question 28.

Solution:

In an AP, T₁₇ = T₁₀ + 21

Let a be the first term and d be the common difference, then

Question 29.

Solution:

Question 30.

Solution:

Hope given RS Aggarwal Solutions Class 10 Chapter 11 Arithmetic Progressions are helpful to complete your math homework.

If you have any doubts, please comment below. A Plus Topper try to provide online math tutoring for you.