NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5, are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

Question 1.

Construct the right-angled ∆ PQR where m ∠Q = 90°, QR = 8 cm and PR = 10 cm.

Solution:

Steps of Construction

1. Draw QR of length 8 cm.
   
   
2. At Q, draw QX ⊥ QR.
3. With R as centre, draw an arc of radius 10 cm.
4. Mark the meeting point of these two as P.

∆ PQR is now obtained.

Question 2.

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Solution:

Steps of Construction

1. Draw QR of length 4 cm.
2. At Q, draw QX ⊥ QR.
   
   
3. With R as centre, draw an arc of radius 6 cm.
4. Mark the meeting point of arc and QX as P.

∆ PQR is now obtained.

Question 3.

Construct an isosceles right-angled triangle ABC where m ∠ACB = 90° and AC = 6 cm.

Solution:

Steps of Construction

1. Draw AC of length 6 cm.
2. At C, draw CX ⊥ CA.
   
   
3. With C as centre, draw an arc of radius 6 cm to intersect CX at B.
4. Join AB.

∆ ACB is now obtained.

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