NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3, are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3

Question 1.

Construct ADEF such that DE = 5 cm, DF 3 cm, and m ∠EDF = 90°.

Solution:

Steps of Construction

1. Draw a line segment DE of length 5 cm.
   
   
2. At D, draw DX making 90° with DE.
3. With D as centre, draw an arc of radius 3 cm. It cuts DX at the point F.
4. Join FE.
   
   ∆ DEF is now obtained.

Question 2.

Construct an isosceles triangle in which the length of each of its equal sides is 6.5 cm and the angle between them is 110°.

Solution:

Steps of Construction

1. Draw a line segment QR of length 6.5 cm.
2. At Q, draw QX making 110° with QR, using a protractor.
   
   
3. With Q as centre, draw an arc of radius 6.5 cm. It cuts QX at P.
4. Join PR
   
   ∆ PQR is now obtained.

Question 3.

Construct ∆ ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.

Solution:

Steps of Construction

1. Draw a line segment BC of length 7.5 cm.
   
   
2. At C, draw CX making 60° with CB
3. With C as centre, draw an arc of radius 5 cm. It cuts CX at A.
4. Join AB. ∆ ABC is now obtained.

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