NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2, are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2.

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Question 1.

Draw a line segment of length 7.3 cm. using a ruler.

Solution :

Using ruler, we mark two points A and B which are 7.3 cm apart. Join A and B and get AB. (overline { AB }) is a line segment of length 7.3 cm.

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 7

Question 2.

Construct a line segment of length 5.6 cm using ruler and compasses.

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 8

Solution :

Step 1. Draw a line l. Mak a point A on line l.

Step 2. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 5.6 cm mark.

Step 3. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.

Step 4. AB is a line segment of required length.

Question 3.

Construct (overline { AB }) of length 7.8 cm. From this cut off (overline { AC }) of length 4.7 cm. Measure (overline { BC }).

Solution :

Steps of Construction

Step 1. Draw a line l. Mark a point A on line l.

Step 2. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 7.8 cm mark.

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 9

Step 3. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.

Step 4. (overline { AB }) is a line segment of length 7.8 cm.

Step 5. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto 4.7 cm mark.

Step 6. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at C.

Step 7. (overline { AC }) is a line segment of length 4.7 cm. On measurement. (overline { BC }) =3.1 cm.

Question 4.

Given (overline { AB }) of length 3.9 cm, construct (overline { PQ }) such that the length of (overline { PQ }) is twice that of AB Verify by measurement.

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 10

(Hint : Construct (overline { PX }) such that length of PX = length of (overline { AB }); then cut off (overline { XQ }) such that (overline { XQ }) also has the length of (overline { AB })).

Solution :

Steps of Construction

Step 1. Draw a line I. Mark a point P on line l.

Step 2. Place the compasses pointer on the A mark of the given line segment (overline { AB }) . Open it to place the pencil point upto B mark of the given line segment (overline { AB }).

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 11

Step 3. Without changing the opening of the compasses, place the pointer on P and swing an arc to cut l at X.

Step 4. Again without changing the opening of the compasses place the compasses pointer on the X mark of line / and swing an arc to cut / at Q.

Step 5. (overline { PQ }) is a line segment of length twice that of (overline { AB }). Please verify yourself by measurement.

Question 5.

Given (overline { AB }) of length 7.3 cm and (overline { CD }) of length 3.4 cm, construct a line segment (overline { XY }) such that the length of (overline { XY }) is equal to the difference between the lengths of (overline { AB }) and (overline { CD }) . Verify by measurement.

Solution :

Steps of Construction

Step 1. Draw a line l. Mark a point X on line l.

Step 2. Place the compasses pointer on the A mark of the given line segment (overline { AB }). Open it to place the pencil point upto B mark of the given line segment (overline { AB }).

Step 3. Without changing the opening of the compasses, place the pointer of compasses on X and swing an arc to cut / at ∠.

Step 4. Place the compasses pointer on the C mark of the given line segment (overline { CD }). Open it to place the pencil point upto D mark of the given line segment (overline { CD }).

Step 5. Without changing the opening of the compasses, place the pointer of compasses on ∠ and swing an arc towards X to cut l at Y.

Step 6. (overline { XY }) is a required line segment of length = the difference between the lengths of (overline { AB }) and (overline { CD }).

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 12

Please verify yourself by measurement.

We hope the NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2, help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2, drop a comment below and we will get back to you at the earliest.

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