Representing Irrational Numbers On The Number Line

Representing Irrational Numbers On The Number Line

Represent  √2 & √3 on the number line:

[youtube https://www.youtube.com/watch?v=2bMKu1CXyB0?feature=oembed]

Greeks discovered this method. Consider a unit square OABC, with each side 1 unit in lenght. Then by using pythagoras theorem

Representing Irrational Numbers On The Number Line 1

(OB=sqrt{1+1}=sqrt{2})

Now, transfer this square onto the number line making sure that the vertex O coincides with zero

Representing Irrational Numbers On The Number Line 2

With O as centre & OB as radius, draw an arc, meeting OX at P. Then

OB = OP = √2 units

Then, the point represents √2 on the number line

Now draw, BD ⊥ OB such that BD = 1 unit join OD. Then

Representing Irrational Numbers On The Number Line 3

OD = (sqrt+}=sqrt{3}) = units With O as centre & OC as radius, draw an arc, meeting OX at Q. Then

OQ = OD = √3 units

Then, the point Q represents √3 on the real line

Remark: In the same way, we can locate √n for any positive integer n, after (sqrt{n-1}) has been located.

[youtube https://www.youtube.com/watch?v=yX0Sz0vKHa8?feature=oembed]

Existence of √n for a positive real number:

The value of √4.3 geometrically : –

Draw a line segment AB = 4.3 units and extend it to C such that BC = 1 unit.

Find the midpoint O of AC.

With O as centre and OA a radius, draw a semicircle.

Representing Irrational Numbers On The Number Line 4

Now, draw BD ⊥ AC, intersecting the semicircle at D. Then, BD = √4.3 units.

With B as centre and BD as radius, draw an arc, meeting AC produced at E.

Then, BE = BD = √4.3 units

[youtube https://www.youtube.com/watch?v=IvfJuL-shLo?feature=oembed]

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