Frank ICSE Solutions for Class 9 Maths – Constructions of Quadrilaterals

Frank ICSE Solutions for Class 9 Maths – Constructions of Quadrilaterals

Ex No: 20.1

Solution 1:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 1

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 2

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 3

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Solution 2:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 5

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 6

Solution 3:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 7

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 8

Solution 4:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 9

Solution 5:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 10

Solution 6:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 11

Solution 7:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 12

Solution 8:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 13

Solution 9:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 14

Solution 10:

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Solution 11:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 16

Solution 12:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 17

Solution 13:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 18

Solution 14(a):

Steps of construction:

Draw AD = 3.2 cm

Draw ∠XAD = 90°.

With D as centre and radius BD = 5.5 cm, draw an arc to cut AX at point B.

Join BD.

With B as centre and radius 3.2 cm draw an arc and with D as centre and radius = AB, draw another arc to cut the previous arc at C.

Join BC and CD.

Thus, ABCD is the required rectangle.

CD = 4.5 cm

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 19

Solution 14(b):

Steps of construction:

Draw BC = 6.2 cm

Through B, draw BP such that ∠B = 90°

From BP, cut BA = 5 cm

With A and C as centres and radii 6.2 cm and 5 cm respectively, draw arcs cutting each other at D.

Join AD and CD.

Thus, ABCD is the required triangle.

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 20

Solution 15:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 21

Solution 16:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 22

Solution 17:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 23

Solution 18(a):

Since area of rectangle = 21 cm2

And, length = 4.2 cm

Breadth = Area ÷ Length = 21 ÷ 4.2 = 5 cm

Steps of construction:

Draw BC = 5 cm

Through B, draw BP such that ∠B = 90°

From BP, cut BA = 4.2 cm

With A and C as centres and radii 5 cm and 4.2 cm respectively, draw arcs cutting each other at D.

Join AD and CD.

Thus, ABCD is the required triangle.

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Solution 18(b):

Since area of rectangle = 33.8 cm2

And, breadth = 6.5 cm

Length = Area ÷ Breadth = 33.8 ÷ 6.5 = 5.2 cm

Steps of construction:

Draw BC = 6.5 cm

Through B, draw BP such that ∠B = 90°

From BP, cut BA = 5.2 cm

With A and C as centres and radii 6.5 cm and 5.2 cm respectively, draw arcs cutting each other at D.

Join AD and CD.

Thus, ABCD is the required triangle.

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 25

Solution 19:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 26

Solution 20:

Frank ICSE Solutions for Class 9 Maths - Constructions of Quadrilaterals 27

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