Calculus: Graphical, Numerical, Algebraic, 3rd Edition Answers Ch 1 Prerequisites for Calculus Ex 1.5

Calculus: Graphical, Numerical, Algebraic, 3rd Edition Answers Ch 1 Prerequisites for Calculus Ex 1.5

Calculus: Graphical, Numerical, Algebraic Answers

Chapter 1 Prerequisites for Calculus Exercise 1.5 1E

The given function is

y = 2|x|

and the graph ot the given function is shown below,

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-1e

We can find out whether a given function is one-to-one or not one-to-one, by drawing a set of horizontal lines on its graph.

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

For this problem the answer is NO, the given function is not one-to-one because it one was to draw horizontal lines on this graph, they will intersect the graph at two points.

Chapter 1 Prerequisites for Calculus Exercise 1.5 1QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-1qr

Chapter 1 Prerequisites for Calculus Exercise 1.5 2E

The given function is

y = x + 1

And the graph of the given function is shown below,

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-2e

We can find out whether a given function is one-to-one or not by drawing a set of horizontal lines on its graph.

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

YES, the given function is one-to-one because if one was to draw horizontal lines on this graph, none of them will intersect the graph at more than one point.

Chapter 1 Prerequisites for Calculus Exercise 1.5 2QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-2qr

Chapter 1 Prerequisites for Calculus Exercise 1.5 3E

The given function is

y = 1/x

and the graph of the given function is shown below,

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-3e

We can find out whether a given function is one-to-one or not by drawing a set of horizontal lines on its graph.

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

For this problem the answer is YES, the given function is one-to-one because if one was to draw horizontal lines on this graph, none of them will intersect the graph at more than one point.(as shown in the above figure)

NOTE:

In the above figure the graph of the given function seems to be touching the X-axis, but it never touches the X-axis, so we can confirm that, there is no parallel line intersects the given function at more than one point.

Chapter 1 Prerequisites for Calculus Exercise 1.5 3QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-3qr

Chapter 1 Prerequisites for Calculus Exercise 1.5 4E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-4e

We can find out whether a given function is one-to-one or not by drawing a set of horizontal lines on its graph.

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

For this problem the answer is No, the given function is not one-to-one because if one was to draw horizontal lines on this graph, they will intersect the graph at two points.

Chapter 1 Prerequisites for Calculus Exercise 1.5 4QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-4qr

Chapter 1 Prerequisites for Calculus Exercise 1.5 5E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-5e

We can find out whether a given function is one-to-one or not by drawing a set of horizontal lines on its graph.

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

For this problem the answer is YES, the given function is one-to-one because if one was to draw horizontal lines on this graph, none of them will intersect the graph at more than one point.

Chapter 1 Prerequisites for Calculus Exercise 1.5 5QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-5qr

Chapter 1 Prerequisites for Calculus Exercise 1.5 6E

The given function is

y = int x

The graph of the given function is shown below,

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-6e

We can find out whether a given function is one-to-one or not by drawing a set of horizontal lines on its graph.

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

For this problem answer is No, the given function is not one-to-one because if one was to draw horizontal lines on this graph, they will intersect the graph at more than one point.

(as shown in the above graph).

Chapter 1 Prerequisites for Calculus Exercise 1.5 6QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-6qr

Chapter 1 Prerequisites for Calculus Exercise 1.5 7E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-7e

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-7e1

The given function is one-to-one because if one was to draw horizontal lines on this graph, none of them will intersect the graph at more than one point.

Hence we can say that the given function has an inverse function.

Chapter 1 Prerequisites for Calculus Exercise 1.5 7QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-7qr

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-7qr1

Chapter 1 Prerequisites for Calculus Exercise 1.5 8E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-8e

The given function is not one-to-one because if one was to draw horizontal lines on this graph, they will intersect the graph at two points.

Hence we can say that the given function does not have an inverse function.

Chapter 1 Prerequisites for Calculus Exercise 1.5 8QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-8qr

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-8qr1

Chapter 1 Prerequisites for Calculus Exercise 1.5 9E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-9e

The given function is not one-to-one because if one was to draw horizontal lines on this graph, they will intersect the graph at two points.

Hence we can say that the given function does not have an inverse function.

Chapter 1 Prerequisites for Calculus Exercise 1.5 9QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-9qr

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-9qr1

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-9qr2

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-9qr3

Chapter 1 Prerequisites for Calculus Exercise 1.5 10E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-10e

The given function is one-to-one because if one was to draw horizontal lines on this graph, none of them will intersect the graph at more than one point.

Hence we can say that the given function has an inverse function.

Chapter 1 Prerequisites for Calculus Exercise 1.5 10QR

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-10qr

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-10qr1

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-10qr2

Chapter 1 Prerequisites for Calculus Exercise 1.5 11E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-11e

The given function is not one-to-one because if one was to draw horizontal lines on this graph, they will intersect the graph at two points.

Hence we can say that the given function does not have an inverse function.

Chapter 1 Prerequisites for Calculus Exercise 1.5 12E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-12e

Chapter 1 Prerequisites for Calculus Exercise 1.5 13E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 14E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 15E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 16E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 17E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 18E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 19E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 20E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 21E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 22E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 23E

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calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-23e2

Chapter 1 Prerequisites for Calculus Exercise 1.5 24E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 25E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 26E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 27E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 28E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 29E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 30E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 31E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 32E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 33E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 34E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 35E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 36E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 37E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 38E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 39E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 40E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 41E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 42E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 43E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 44E

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calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-44e1

Chapter 1 Prerequisites for Calculus Exercise 1.5 45E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 46E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 47E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 48E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 49E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 50E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-50e

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Chapter 1 Prerequisites for Calculus Exercise 1.5 51E

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calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-51e1

Chapter 1 Prerequisites for Calculus Exercise 1.5 52E

We can find out whether a given function is one-to-one or not by drawing a set of horizontal lines on its graph.

The given graph is shown below

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-52e

If any horizontal line intersects the graph at more than one point, then the given function will not be one-to-one.

No, the given function is not one-to-one because if one was to draw horizontal lines on this graph, they will intersect the graph at two points or more at some points.

Hence the given statement is FALSE.

Chapter 1 Prerequisites for Calculus Exercise 1.5 53E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-53e

Chapter 1 Prerequisites for Calculus Exercise 1.5 54E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 55E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-55e

Chapter 1 Prerequisites for Calculus Exercise 1.5 56E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-56e

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Chapter 1 Prerequisites for Calculus Exercise 1.5 57E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 58E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-58e

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Chapter 1 Prerequisites for Calculus Exercise 1.5 59E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 60E

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Chapter 1 Prerequisites for Calculus Exercise 1.5 61E

calculus-graphical-numerical-algebraic-3rd-edition-answers-ch-1-prerequisites-calculus-ex-1.5-61e

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Chapter 1 Prerequisites for Calculus Exercise 1.5 62E

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