


Types Of Factorization Example Problems With Solutions
Type I: Factorization by taking out the common factors.
Example 1: Factorize the following expression
2x2y + 6xy2 + 10x2y2
Solution: 2x2y + 6xy2 + 10x2y2
=2xy(x + 3y + 5xy)
Type II: Factorization by grouping the terms.
Example 2: Factorize the following expression
a2 – b + ab – a
Solution: a2 – b + ab – a
= a2 + ab – b – a = (a2 + ab) – (b + a)
= a (a + b) – (a + b) = (a + b) (a – 1)
Type III: Factorization by making a perfect square.

Example 3: Factorize of the following expression
9x2 + 12xy + 4y2
Solution: 9x2 + 12xy + 4y2
= (3x)2 + 2 × (3x) × (2y) + (2y)2
= (3x + 2y)2
Example 4: Factorize of the following expression
(frac}}+2+frac}},xne 0,yne 0)
Solution:
Example 5: Factorize of the following expression
(+4left( 5x-frac{1}{x} right)+4,xne 0)
Solution:
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Type IV: Factorizing by difference of two squares.
Example 6: Factorize the following expressions
(a) 2x2y + 6 xy2 + 10 x2y2
(b) 2x4 + 2x3y + 3xy2 + 3y3
Solution:
Example 7: Factorize 4x2 + 12 xy + 9 y2
Solution:
Example 8: Factorize each of the following expressions
(i) 9x2 – 4y2
(ii) x3 – x
Solution:
Example 9: Factorize each of the following expressions
(i) 36x2 – 12x + 1 – 25y2
(text{(ii) }-frac{9}},ane 0)
Solution:
Example 10: Factorize the following algebraic expression
x4 – 81y4
Solution:
Example 11: Factorize the following expression
x(x+z) – y (y+z)
Solution: x(x+z) – y (y+z) = (x2 – y2) + (xz–yz)
= (x–y) (x+y) + z (x–y)
= (x–y) {(x+y) + z}
= (x–y) (x+ y + z)
Example 12: Factorize the following expression
x4 + x2 + 1
Solution: x4 + x2 + 1 = (x4 + 2x2 +1) – x2
= (x2 +1)2 – x2 = (x2 + 1 – x) (x2 + 1+x)
= (x2–x + 1) (x2 + x + 1)
Type V: Factorizing the sum and difference of cubes of two quantities.
(i) (a3 + b3) = (a + b) (a2 – ab + b2)
(ii) (a3 – b3) = (a – b) (a2 + ab + b2)
Example 13: Factorize the following expression
a3 + 27
Solution: a3 + 27 = a3 + 33 = (a + 3) (a2 –3a +9)
Example 14: Simplify : (x+ y)3 – (x –y)3 – 6y(x2 – y2)
Solution:
