 # Factorization Of Algebraic Expressions  ## Factorization Of Algebraic Expressions Of The Form a3 + b3 + c3, When a + b + c = 0

Example 1:   Factorize (x – y)3 + (y – z)3 + (z – x)3

Solution:    Let x – y = a, y– z = b and z – x = c, then,

a + b + c = x – y + y – z + z –x = 0

∴ a3 + b3 + c3 = 3abc

⇒ (x – y)3 + (y – z)3 + (z – x)3 = 3 (x–y)(y – z)(z–x)

Example 2:    Factorize  (a2–b2)3 + (b2–c2)3+ (c2–a2)3

Solution:    We have,

Example 3:    (text{Simplify }frac-)}^{3}}+-)}^{3}}+-)}^{3}}}++})

Solution:    We have,

Example 4:    Find the value of x3 – 8y3 – 36 xy – 216, when x = 2y + 6.

Solution:    We have,

FACTORIZATION OF x3 ± y3

In order to factorize the algebraic expression expressible as the sum or difference of two cubes, we sue the following identities.

(i) x3 + y3 = (x + y) (x2 – xy+ y2)

(ii) x3 – y3 = (x – y) (x2 + xy + y2) Example 5:    Factorize 27x3 + 64y3

Solution:    27x3 + 64y3

= (3x + 4y) {(3x)2 – (3x) (4y) + (4y)2},

= (3x + 4y) (9x2 – 12 xy + 16y2)

Example 6:    Factorize a3 + 3a2b + 3ab2 + b3 – 8

Solution:    Factorize a3 + 3a2b + 3ab2 + b3 – 8

= (a + b)3 –23

= {(a+b) – 2} {(a +b)2 +(a +b).2+22}

= (a + b– 2) (a2 + 2ab + b2 +2a + 2b + 4)

Example 7:    Factorize : a3 – 0.216

Solution:    a3 – 0.216

= a3 – (0.6)3

= (a –0.6) [a2 + 0.6a +(0.6)2]

= (a–0.6) (a2 + 0.6 a + 0.36)

Example 8:    Factorize:

(i) (x+ 1)– (x–1)3 (ii) 8(x + y)3 – 27 (x–y)3

Solution:

Example 9:    Factorize:  (i) x6 – y6 (ii) x12 – y12

Solution:

Example 10:   Prove that:

(frac{0.87times 0.87times 0.87+0.13times 0.13times 0.13}{0.87times 0.87-0.87times 0.13+0.13times 0.13}=1)

Solution:    We have,

FACTORIZATION OF x3 + y3 + z3 – 3 xyz

(i) In order to factorize the algebraic expressions of the form x3 + y3 + z3 – 3 xyz

We use the following identity:

(i) x3 + y3 + z3 – 3 xyz = (x+y+z) (x2 + y2 + z2–xy – yz – zx)

(ii) If x + y + z = 0, then x3 + y3 + z3 = 3xyz

Example 11:   Factorize: 8x3 + 27y3+ z3 – 18 xyz

Solution:    We have,

Example 12:    Factorize :  (a+b)3 + (b+c)+ (c+a)3 – 3(a+ b) (b+c) (c+a)

Solution:    We have,

Example 13:    Resolve a3 – b3 + 1 + 3ab into factors

Solution:   a3 – b3 + 1 + 3ab

Example 14:    Factorize : 2√2 a3+ 8b3 – 27c3 + 18√2 abc

Solution:    2√2 a3+ 8b3 – 27c3 + 18√2 abc

Example 15:    Prove that:

a3 + b3 + c3 – 3abc =  1/2 (a+b+c) {(a–b)2 +  (b–c)2 + (c–a)2}

Solution:    We have, You might also like 